Friday, January 15, 2010

compute the Average of Turn Around Time of the following process scheduling algorithm


Arrival Time:    0    1    2    3   4   5   6   7   8   9   10

Job Name:         A    B   C    D   E   F  G  H  I   J    K    

CPU Cycle:        5     2   8    4   3    1   2   9  7   3   4(ms)

Time Quantum:   2


Answers:

a.       a. FCFS

Job A

Job B

Job C

Job D

Job E

Job F

Job G

Job H

Job I

Job J

Job K

0-5

7

15

19

22

23

25

34

41

44

48

 

ATT = 5+7+15+19+22+23+25+34+41+44+48 = 25.73

                                      11

 

b.      b. SJN

Job F

Job B

Job G

Job E

Job J

Job D

Job K

Job A

Job I

Job C

Job H

0-1

3

5

8

11

15

19

24

31

39

48

 

ATT = 1+3+5+8+11+15+19+24+31+39+48 = 18.55

                                     11


a.       d. Round-Robin

Job A

Job B

Job C

Job D

Job E

Job F

Job G

Job H

Job I

Job J

Job K

Job A

Job C

Job D

Job E

Job H

Job I

0-2

4

6

8

10

11

13

15

17

19

21

23

25

27

28

30

32

 

Job J

Job K

Job A

Job C

Job H

Job I

Job C

Job H

Job I

Job H

33

35

36

38

40

42

44

46

47

48

 

 ATT = 36+3+42+24+24+6+7+41+39+24+25 = 24.64

                                                        11


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